Calculating Power Dissipation in Series Lightbulb Circuit

Thread starter BuBbLeS01
Start date Feb 7, 2008
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Power

AI Thread Summary

In a series circuit with two 97 W lightbulbs connected to a 114 V supply, the total resistance is 228 ohms. The current through the circuit is calculated as 0.5 A using the formula I = E/Req. Each bulb dissipates power calculated by P = VI, resulting in 57 W per bulb. However, this calculation is incorrect as it does not account for the voltage drop across each bulb in series. Proper analysis shows that each bulb actually dissipates less power due to the shared voltage, leading to a need for reevaluation of the calculations.

Feb 7, 2008

BuBbLeS01

Power...Did I do this right??

Homework Statement

Two 97 W (114 V) lightbulbs are wired in series, then the combination is connected to a 114 V supply. How much power is dissipated by each bulb?

Homework Equations

P = VI
I = E/Req

The Attempt at a Solution

I = 114/228 =0.5
P = 0.5 * 114 = 57
Is this right?

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Feb 7, 2008

BuBbLeS01

Oh my gosh its wrong! Why am I not getting these Power problems right! I thought that was the equation...

Feb 7, 2008

BuBbLeS01

solved...

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