Power dissapatied by a resistor

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The discussion centers on calculating the power dissipated by a resistor (R1) in a circuit with two resistors in series. The user initially applies the formula for equivalent resistance in parallel instead of series, leading to confusion in their calculations. They correctly identify the current using I=V/R but mistakenly apply the wrong resistance formula. The conversation highlights the importance of using the correct formulas for series and parallel circuits to accurately determine power dissipation. Clarification is needed on the correct approach to solve the problem.
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Homework Statement



How much power is dissipated by R1 resistor? (R1=15 W, R2=25 W, V=9 V.)

Resistor.jpg


Homework Equations



I=V/R

P=I^2R

The Attempt at a Solution


Since it is a series 1/Req=(1/R1)+(1/R2)

Then I=V/R= .96 A

so Then i just simply plugged in I in P=I^2R which is apparently wrong, but I thought this is right. What am i doing wrong?
 

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You are right, the resistors are in series. So why are you using the Req formula for resistors in parallel?
 
...let me get back to you
 

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