Power Flows and Losses in a line between two buses

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SUMMARY

The discussion focuses on the calculation of power flows and losses between two buses in a power system. The participant clarifies that the losses should be calculated using the voltage difference (V2-V3) multiplied by the current (I23), rather than using the conjugate current. The reactive power loss is computed as Qloss = Iabs^2 * Xcap, where Xcap is the capacitive reactance of 0.1 ohms. The reference for the calculations is Mr. Hadi Saadat's "Power System Analysis," specifically chapter 6, which addresses power flow analysis.

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Electrical engineers, power system analysts, and students studying power flow analysis will benefit from this discussion, particularly those focusing on reactive power calculations and bus system interactions.

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Homework Statement
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Relevant Equations
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Question:
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Equations:
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My solution:
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Could someone verify my answer?
 
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I apologize for the delay. At first glance it seemed complicated especially because Ybus = 0. in reality it is much easier because the voltages and powers are already calculated.
The calculation seems correct to me except for the losses between 2 and 3 which must be the product of V2-V3 voltage with the current and not V2 with the current conjugated as for the flow. There are not actual losses since no resistance is there but only a capacitor of 0.1 ohm reactance. That means the reactive power produced in there it is I^2*Xcap
If I23=0.038-0.053i and Iabs=0.0652 the Qloss=0.0652^2*0.1=0.0004253 [Var] p.u.
The product (V2-V3)*I23=-0.0004253 [Var] p.u. also.
 
Last edited:
Sorry. Following the publication of Mr. Hadi Saadat

Power System Analysis chapter 6 Power Flow Analysis Example 6.7

it turns out that I was wrong and you are right.

I am still very busy and I have no time to check this.
 

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