Power input of a Force acting on a particle moving with Velocity

AI Thread Summary
The discussion focuses on calculating the power input of a force acting on a particle moving with a given velocity using the formula P = F • v. The first example yielded a correct power output of 28 W, while the second example resulted in -55 W due to the opposing directions of the force and velocity components. The third example, which should yield 34 W, posed difficulties for the participant, highlighting confusion around the dot product and the use of magnitudes and angles. Clarifications were provided on how to approach the calculations correctly, emphasizing the importance of considering vector directions and components. Overall, the conversation illustrates the challenges of applying vector mathematics in physics problems.
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Homework Statement



Find the power input of a force \vec{F} acting on a particle that moves with a velocity \vec{V} for each of the following situations.

  • \vec{F} = 4\hat{i} N  + 3\hat{j} N , \vec{V} = 7\hat{i} m/s 
  • \vec{F} = 7\hat{i} N  - 5\hat{j} N , \vec{V} = -5\hat{i} m/s + 4\hat{j} m/s 
  • \vec{F} = 2\hat{i} N + 10\hat{j} N , \vec{V} = 2\hat{i} m/s  + 3\hat{j} m/s 

Homework Equations



P = \frac{dW}{dt} = \vec{F} • \vec{v}

The Attempt at a Solution



  • \sqrt{4^2 + 3^2} \times cos(arctan(3/4)) \times 7
    For this problem, I got the correct answer: 28 W.
  • \sqrt{7^2 + (-5)^2} \times \sqrt{(-5)^2 + 4^2}
    I also got the correct answer for this problem: 55 W, except that the answer is negative, I figure because the velocity vector's \hat{i} and \hat{j} components are in the opposite direction of the force's components (individually). Is this supposition correct?
  • \sqrt{2^2 + 10^2} \times sin(arctan(10/2)) \times \sqrt{2^2 + 3^2} \times sin(arctan(3/2))
    I cannot figure out what I am doing wrong on this one. (The correct answer is 34.)

I am having a hard time wrapping by head around dot products. I'm guess that is my problem here. Any and all help is greatly appreciated.
 
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When you do dot products, you take the sum of the products of each component.
For the first one:
P = 4N*7m/s (the i components) + 3N*0m/s (the j components) = 28 W.
For the second one:
P=7N*-5m/s (i components) + -5N*4m/s (j components) = -55W.
Try the third one out this way.
P= (product of i components) + (product of j components) = ?
 
What you are doing is finding it using magnitudes and angles, which you must first calculate. When calculating angles, you also have to think about the fact that it may be more than 90 degrees, something that arctan will not provide.
 
OK, thanks. I completely get how to do this in the future.

Regarding your second comment though -- I understand about arctan. I drew a diagram so I knew where my vectors were. Was this comment just FYI or was my attempted method something that would work, I was just simply doing it incorrectly?
 
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