Power mechanics physics problem

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SUMMARY

The discussion centers on calculating the average speed required for a 50kg student to match a power output of 200W while climbing a 5.0m rope. The key equations utilized include Work = mgh and Power = Work/time. The student needs to determine the time taken to climb the rope to find the average speed. The calculations lead to the conclusion that the average speed must be approximately 0.41m/s to achieve the desired power output.

PREREQUISITES
  • Understanding of basic physics concepts such as work, power, and energy.
  • Familiarity with the equations Work = mgh and Power = Work/time.
  • Knowledge of average speed calculations.
  • Ability to manipulate algebraic equations to solve for unknown variables.
NEXT STEPS
  • Review the principles of mechanical work and energy in physics.
  • Study the relationship between power, work, and time in various contexts.
  • Explore examples of average speed calculations in physics problems.
  • Learn about the implications of power output in physical activities and sports science.
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the relationship between power, work, and motion in physical scenarios.

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A 50kg student climbs a 5.0m long rope and stops at the top.What must her average speed be in order to match the power output of 200w.
a)0.20m/s
b)0.41m/s
c)0.10m/s

My Work :
And stops at the top => v=0 and h=5m so I'll use mgh.
Now power output = variation of energy/1

But average means the variation of x /variation in time.

Any help will be great,
Thanks
 
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How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?
 


Doc Al said:
How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?

Work = mgh , where h=5

Power = Work/time

time = Work / power

Average speed = 5 / time(gotten) ?
 


Sounds good to me.
 

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