Power mechanics physics problem

[-Aladdin-]

A 50kg student climbs a 5.0m long rope and stops at the top.What must her average speed be in order to match the power output of 200w.
a)0.20m/s
b)0.41m/s
c)0.10m/s

My Work :
And stops at the top => v=0 and h=5m so I'll use mgh.
Now power output = variation of energy/1

But average means the variation of x /variation in time.

Any help will be great,
Thanks

 

[Doc Al]

How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?

 

[-Aladdin-]

How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?

Work = mgh , where h=5

Power = Work/time

time = Work / power

Average speed = 5 / time(gotten) ?

 

[Doc Al]

Sounds good to me.