Power Series expansion of hyperbolic functions

thanksie037
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Homework Statement



power series expansion of:

((cosh x)/(sinh x)) - (1/x)


Homework Equations



cosh x = (1/2)(ex + e-x)
sinh x = (1/2)(ex - e-x)

The Attempt at a Solution


what i have so far:

I simplified the first part of the eq to read :
e2x-1
e2x-1


now I am stuck. please help
 
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You simplified for it to be \frac{e^{2x}-1}{e^{2x}-1}? Isn't that just 1?
 
error in simplification:

\frac{e^{2x}+1}{e^{2x}-1}
 
I'm sorry that was a typo. Should I just expand both was like you would ex? how about the 1/x part?
 
I would and then hopefully things will cancel, for example what's the expansion for e^{2x} - 1?
 
How do one usually find the taylor series of a given function?
now you have a function, what do you do? :rolleyes:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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