Power Series expansion of hyperbolic functions

thanksie037
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Homework Statement



power series expansion of:

((cosh x)/(sinh x)) - (1/x)


Homework Equations



cosh x = (1/2)(ex + e-x)
sinh x = (1/2)(ex - e-x)

The Attempt at a Solution


what i have so far:

I simplified the first part of the eq to read :
e2x-1
e2x-1


now I am stuck. please help
 
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You simplified for it to be \frac{e^{2x}-1}{e^{2x}-1}? Isn't that just 1?
 
error in simplification:

\frac{e^{2x}+1}{e^{2x}-1}
 
I'm sorry that was a typo. Should I just expand both was like you would ex? how about the 1/x part?
 
I would and then hopefully things will cancel, for example what's the expansion for e^{2x} - 1?
 
How do one usually find the taylor series of a given function?
now you have a function, what do you do? :rolleyes:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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