# Power supplied by battery in a multiple loop Circuit

1. Feb 13, 2008

### snoweangel27

1. The problem statement, all variables and given/known data
I am given the circuit, which is shown in the attachment, and I need to calculate the power supplied from each of the 12V batteries.

2. Relevant equations
I have already solved for the current in each resistor and the potential difference between a and b.

The only equation I know to use is P= IV, where I am calculating I by dividing V/R(equivalence)

3. The attempt at a solution

I have tried solving this multiple times, all without success. My most current attempt at the Power supplied from the right side was finding R(equivalence) = 9 the using I=V/R, then using the new R (4/3) in P=IV P=(4/3 A)*12V, where P=8, which I thought was a rather low number.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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• ###### F26-59.JPG
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2. Feb 13, 2008

### rohanprabhu

ur attachment is pending approval.. why dont u upload it somewhere.. like: http://bayimg.com [Broken] and then post it here so that it becomes available immediately.

Last edited by a moderator: Apr 23, 2017 at 10:49 AM
3. Feb 13, 2008

### snoweangel27

Sorry, I just didn't think about it.

"http://i2.photobucket.com/albums/y30/snoweangel27/F26-59.jpg" [Broken]

Last edited by a moderator: Apr 23, 2017 at 10:49 AM
4. Feb 13, 2008

### rohanprabhu

Use Kirchoff's law to find the amount of current flowing in each branch i.e. through each resistor. Once you've done that, use the formula:

$$P = I^2R$$

to find the power dissipated.

5. Feb 13, 2008

### snoweangel27

Should I calculate the Power dissipated from each resistor in the loop then sum them to get the total power?

Last edited: Feb 13, 2008
6. Feb 14, 2008

### kamerling

If you sum $$I^2R$$ for all the resistances in the circuit that will give you the total power delivered by both voltage sources. But you need the power of each of them separately.

A voltage source with potential difference $$V$$ that delivers a current $$I$$ delivers a power $$VI$$

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