Power supplied by battery in a multiple loop Circuit

[snoweangel27]

Homework Statement

I am given the circuit, which is shown in the attachment, and I need to calculate the power supplied from each of the 12V batteries.

Homework Equations

I have already solved for the current in each resistor and the potential difference between a and b.

The only equation I know to use is P= IV, where I am calculating I by dividing V/R(equivalence)

The Attempt at a Solution

I have tried solving this multiple times, all without success. My most current attempt at the Power supplied from the right side was finding R(equivalence) = 9 the using I=V/R, then using the new R (4/3) in P=IV P=(4/3 A)*12V, where P=8, which I thought was a rather low number.

 

[rohanprabhu]

ur attachment is pending approval.. why don't u upload it somewhere.. like: http://bayimg.com and then post it here so that it becomes available immediately.

 

[snoweangel27]

Sorry, I just didn't think about it.

http://i2.photobucket.com/albums/y30/snoweangel27/F26-59.jpg"

 

[rohanprabhu]

Use Kirchoff's law to find the amount of current flowing in each branch i.e. through each resistor. Once you've done that, use the formula:

$$P = I^2R$$

to find the power dissipated.

 

[snoweangel27]

Should I calculate the Power dissipated from each resistor in the loop then sum them to get the total power?

 

[kamerling]

Should I calculate the Power dissipated from each resistor in the loop then sum them to get the total power?

If you sum $$I^2R$$ for all the resistances in the circuit that will give you the total power delivered by both voltage sources. But you need the power of each of them separately.

A voltage source with potential difference $$V$$ that delivers a current $$I$$ delivers a power $$VI$$