Pressure and Force in Fluid Dynamics: Clarifying the Application of Pascal's Law

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In the discussion on Pascal's Law and fluid dynamics, the scenario involves a horizontal tube with differing cross-sectional areas and applied forces. When a force of 100N is applied to a 10m² area, it generates a pressure of 10Pa, resulting in a push of only 10N at the 1m² area, leading to an imbalance that suggests continuous fluid movement towards the smaller area. The confusion arises when an additional force of 11N is applied on the 1m² side while the 100N remains on the larger side; the pressure inside the fluid will still be 10Pa, as it is determined by the larger area’s applied force. The fluid will move towards the 1m² side due to the net force created by the 11N opposing the 10N resistance. The analysis should incorporate the Bernoulli equation without accounting for viscous frictional pressure drops.
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Appreciate all assistance in clearing my flow of thoughts with regards to the topic on Pascal Law...

Scenario : A horizontal tube (consisting of fluid) having an area of 10m2 and 1m2 on opposite side
If I were to exert a force of 100N on one side of a surface of 10m2(pressure will then be 10Pa), according to Pascal law, the pressure within the fluid will be 10Pa. Consequently, at the 1m2 side i will only be able to push overcome a resistance of 10N.
Does this means that since there is an inbalance of forces(100N vs 10N), the fluid will keep moving towards the direction of smaller area indefinitely if the condition remain??

My confusion arise here : Say if I to exert a force of 11N on the 1m2 side, with the force of 100N still acting on the 10m2 surface, what will the pressure inside the liquid be(10Pa or 11Pa). Also, in which direction will the fluid move??

Thanks!
 
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The OP should be analyzing this using the Bernoulli equation. Also, no consideration is given to viscous frictional pressure drop.
 

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