Pressure at the bottom of a glass pipe?

AI Thread Summary
To find the pressure at the bottom of a glass pipe filled with water, olive oil, and mercury, the total weight of the liquids must be calculated. The pressure at the bottom is determined using the formula P = Po + ρgd, where Po is the atmospheric pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and d is the height of the liquid column. Since the individual heights of each liquid are not required, the focus is on the total mass and the cross-sectional area of the pipe. The combined weight of the three liquids contributes to the overall pressure experienced at the bottom. Understanding these principles allows for accurate pressure calculations in fluid mechanics.
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Homework Statement


Given a cross sectional area of A=10cm^2
1kg each of water ( ρ = 1000 kg/m^3 ), olive oil (
ρ = 800 kg/m^3 ), and mercury ( ρ = 13600 kg/m^3 ) are poured, and allowed to settle. What is the
pressure at the bottom of the pipe?

Homework Equations


F=PA
P=Po+ρgd

The Attempt at a Solution


I have set up a free body diagram of the system with ∑Fy= PA-mg-PoA= o, but I'm not sure what to do at this point.
 
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Solve for the pressure at the bottom?
 
You know how much total mass is supported by the bottom surface. You know the acceleration of gravity. You know the area of the bottom surface. Calculating the heights or incremental pressures from the individual sections is not necessary.
 
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What is the total weight of liquid?
 
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