Hi everyone, I have a problem (which is likely to be fairly simple), which I need a hand to resolve. I'm trying to determine the impact of changing the internal diameter of the hose/fitting system in a compressed air system (in this case a portable compressor, with an inbuilt air receiver). The starting information is as follows... Compressed air tank outlet diameter: 3/8" ID (9.525mm) Compressed air tank pressure: 160 psi (1,103.16 kPa) Compressed air tank size: 1.94231 cubic feet (55L) Piping and fitting size: 1/4" ID (6.35mm) Hose length: 20m The system is fitted with a 1/4" ID pressure regulator, straight after the outlet from the air reciever, and this regulator is set to 90 PSI. The question is, since the receiver has a 3/8 outlet but is being constricted by the air hose and fittings 1/4 ID, how much extra air flow could I expect to gain by moving to a 3/8 ID hose and fitting system? Somewhat more specifically, I'm looking at this from the point of the peak torque output from an impact wrench. I'm not certain what factors influence the torque output of these tools, but most of them list a peak air requirement (in L/min or cubic feet per minute) which I assume would correlate with the published peak torque (up to the devices engineered safety limits etc). Most have a maximum operating pressure of 90 PSI, hence the regulator setting. All other things being equal (and assuming i don't exceed any engineered limits on the pneumatic tool), I would anticipate better performance from the tool if the air hose and fitting system all the way from the receiver outlet was of a larger ID (3/8 vs 1/4), the real question is, how much better...?