1. The problem statement, all variables and given/known data Water flows at 3.64 L/s through a horizontal pipe that narrows smoothly from 10.2 cm diameter to 4.89 cm diameter. A pressure gauge in the narrow section reads 47.0 kPa. What is the reading of a pressure gauge in the wide section? 2. Relevant equations F=PA P1+ [tex]\rho[/tex]gh+0.5*[tex]\rho[/tex]V2=P2+[tex]\rho[/tex]gh+o.5*[tex]\rho[/tex]V2 3. The attempt at a solution so first thing i did was convert 3.64L/s to 3.64x10-3 m3/s and then found the area of each part of the opening. since they tell me the gauge reading at the narrow end (4.89cm) i used F=PA to find the force. using this force and the area of the wide end (10.2cm) i got a P. this was wrong..can someone tell me what i'm doing wrong??