Pressure of Inert Gas in kN/m^2: 167.82 | Well-Type Manometer

AI Thread Summary
The discussion revolves around calculating the pressure of inert gas using a well-type mercury manometer with given parameters. The user initially struggles with understanding the problem and seeks guidance on how to approach it. After some interaction, they identify the relevant formula involving fluid dynamics and atmospheric pressure. The user successfully applies the formula, incorporating the density of mercury and the height of the measuring column, ultimately arriving at the correct pressure of 167.82 kN/m^2. This calculation demonstrates the application of fluid dynamics principles in measuring gas pressure.
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Homework: Misplaced Thread
A well-type mercury manometer has a well of 0.02m^2 area and a tube of 40mm^2 area. The liquid has a density of 13,534 kg/m^3.Given that the tube is open to the atmosphere and the well is connected to the inert gas manometer was to measure:
Calculate the pressure of the inert gas in kN/m^2 if the height of the measuring column is 500 mm.

The answer given is 167.82kN/m^2.
 
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I can't get the ans, need help with this question
 
You must show us your work. What have you tried so far?
 
anorlunda said:
You must show us your work. What have you tried so far?
So sorry is my first time asking a question here. The main problem here is, I don't really know how to start, totally don't understand the question. Need some guides
 
Well, what have you studied? Do you know the math of fluid dynamics? What course does this homework come from?
 
anorlunda said:
Well, what have you studied? Do you know the math of fluid dynamics? What course does this homework come from?
Currently I am in the marine engineering course. And we are not studying the chapter "measurement of process pressure" we just learned how to find the differential pressure, so there are a few equation u can use to find it.
 
Manage to solve it. So basically I use the formula p2-p1=density*g*h(a/A+1)
So for this question since it stated that its open to the atmosphere thus p1 will equal to the standard atmospheric pressure which is 1.013*10^5 N/M^2, which I didn't know it at first.
So this is how I did it :
P2- (1.013*10^5) =13534*9.81*0.5(40*10^6/0.02 +1)
P2=167817 (N/m^2) / 167.82 (kN/m^2)
 
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