# Prime number theorem

peteryellow
We have that

$P(x) = \sum_{k=1}^{\infty} \frac 1k \pi(x^{1/k})$
and
$Li(x) = \int_2^n \frac {dt}{\log t}$

And the prime number theorem is:

$$\pi(n) \sim \frac{n}{\log n }$$
I want to show that $$P(x) \sim Li(x)$$ is equivalent to prime number theorem.

Homework Helper
\sim is transitive, so it suffices to show that
$$\operatorname{Li}(x)\sim x/\log(x)$$

peteryellow
I have shown this but still I need to show that P(x) \sim Li(x).

Homework Helper
Then you're done:
1. $$\pi(x)\sim x/\log(x)$$ (Prime Number Theorem)
2. $$\operatorname{Li}(x)\sim x/\log(x)$$ (you said you proved it already)
3. $$\pi(x)\sim\operatorname{Li}(x)$$ (by transitivity of ~)

peteryellow
I wish I was done but I am not how can I prove that P(x) \sim Li(x).

P is different from /pi. Give any suggestion how can I prove this.