Prism Question: need this by tonight

  • Thread starter Thread starter jeslyn
  • Start date Start date
  • Tags Tags
    Prism
AI Thread Summary
The discussion revolves around calculating the deviation of a light ray passing through a prism with a +500D mirror at a 30-degree incident angle. The user is uncertain how to proceed due to the lack of information on the prism's index and the alpha angle. They present several potential answers, leaning towards 60 degrees but expressing confusion about the necessary calculations. The key equations for refraction and deviation are noted, but the absence of specific values hinders progress. Ultimately, the user seeks guidance on how to solve the problem effectively.
jeslyn
Messages
1
Reaction score
0

Homework Statement



A light ray has an incident angle of 30 degrees onto the vertex of a +500D mirror in air (directly on the optical axis). By how many degrees is the light ray deviated from its original path?


Homework Equations



n (delta) = (n'-n) (alpha)

n'= [ n sin [(alpha + delta)/2] / [sin (alpha /2)]

alpha = i1' + i2

n sin i1 = n' sin i1'

n' sin i2 = n sin i2'

but the prism index is not given and the alpha angle is not given so I don't know how to approach this question.

The Attempt at a Solution



choices are:
a. 0 degree
b. 30 degrees
c. 60 degrees
d. 90 degrees
e. 120 degrees
 
Last edited:
Physics news on Phys.org
I think the answer is c. 60 degrees but I don't know how to solve it without the prism index and the alpha angle.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top