Probability of finding a particle in the ground state

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SUMMARY

The discussion focuses on calculating the probability of finding a particle in the ground state when its energy is measured, specifically for a particle in a one-dimensional box defined by the wave function \(\psi(x) = \frac{1}{\sqrt{L}}\) in the region \(0 < x < L\). The solution involves using Fourier Series to express the initial wave function in terms of the normalized solutions to Schrödinger's equation, leading to the conclusion that the probability of the particle being in the ground state is \(\frac{8}{\pi^2}\). The wave function is confirmed to be normalized, validating the approach taken.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly wave functions
  • Familiarity with Fourier Series and their application in quantum mechanics
  • Knowledge of Schrödinger's equation and its solutions for a particle in a box
  • Basic calculus, particularly integration techniques
NEXT STEPS
  • Study the derivation of Fourier coefficients in quantum mechanics
  • Learn about the normalization of wave functions in quantum systems
  • Explore the implications of the particle in a box model on quantum states
  • Investigate the relationship between energy levels and wave functions in quantum mechanics
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Students and educators in quantum mechanics, physicists working on wave function analysis, and anyone interested in the mathematical foundations of quantum states and probabilities.

Sam Harrison
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Homework Statement



A particle is prepared in the state \psi (x) = \frac{1}{\sqrt{L}} in a region 0 &lt; x &lt; L between two hard walls (particle in a box). Calculate the probability that the particle is found in the ground state when its energy is measured.

Homework Equations



This question is worth 10 marks, so I presume it's not as simple as squaring the wave function to find the probability. However I'm just not sure what else to do, a hint in the right direction would be greatly appreciated.


The Attempt at a Solution



\left| \psi (x) \right|^{2} = \frac{1}{L}

That's all I can think of doing. I've checked the given wave function is normalised, which it is.
 
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You need to use Fourier Series. You know the normalised solution to Schrodingers equation is root(2/L)sin(nPix/L)

Let the initial wave function be f(x)=1/root(L)

So f(x)=root(2/L)[sum of (c_n)sin(nPix/L)

So c_n=root(2/L)Integral 0 to L of f(x)sin(nPix/L) by Fourier methods

The probability of a particular state is the square of c_n if the wave function is normalised. I make your answer 8/(Pi)^2

Does that make sense?
 

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