Probability question I can't work out

  • Thread starter Thread starter star01
  • Start date Start date
  • Tags Tags
    Probability Work
Click For Summary
SUMMARY

The discussion centers on solving a conditional probability problem involving events A and B, where event C occurs if exactly one of A or B occurs. The correct formula to derive is Pr(C) = Pr(A) + Pr(B) - 2Pr(A ∩ B). The user suggests that C can be expressed as the union of mutually exclusive events (A-B) and (B-A), leading to the evaluation of probabilities to confirm the result. This approach utilizes basic probability axioms and set-theoretic principles.

PREREQUISITES
  • Understanding of conditional probability concepts
  • Familiarity with probability axioms and properties
  • Basic knowledge of set theory, particularly unions and intersections
  • Ability to manipulate algebraic expressions in probability
NEXT STEPS
  • Study the derivation of conditional probability formulas
  • Learn about mutually exclusive events and their implications in probability
  • Explore advanced topics in probability theory, such as Bayes' theorem
  • Practice problems involving set operations in probability
USEFUL FOR

Students studying probability theory, educators teaching conditional probability, and anyone looking to strengthen their understanding of basic probability concepts.

star01
Messages
1
Reaction score
0
Hey

I've just joined here and I'm doing some revision on conditional probability. This one question, which I know should be simple, has me stumped. I've tried what I can think of but I can't seem to get it right. Any help anyone may have would be very much appreciated.

Suppose A and B are events and de ne the new event C to occur if and only if
exactly one of A or B occur. Show algebraically, using only the probability axioms and
properties, and basic set-theoretic results given in the lectures, that
Pr(C) = Pr(A) + Pr(B) - 2Pr(A n B)

Thank you
 
Physics news on Phys.org
C=(A-B) or (B-A), which are mutually exclusive events.. Evaluate probabilities to get result.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
850
  • · Replies 4 ·
Replies
4
Views
2K