Problem about uncertainty principle

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Homework Help Overview

The discussion revolves around the uncertainty principle in quantum mechanics, specifically in the context of an electron pulse characterized by a width of 1 nanosecond and a kinetic energy of 1 keV. Participants are exploring the implications of these parameters on the uncertainties in position (Δx) and momentum (Δp).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the relationship between kinetic energy and momentum, particularly whether knowing the kinetic energy implies zero uncertainty in momentum. There is also discussion on how to derive position uncertainty from the given pulse width.

Discussion Status

The conversation is active, with participants providing insights into the uncertainties involved. Some guidance has been offered regarding the interpretation of the pulse width, and one participant indicates they have resolved their misunderstanding about the 1 ns parameter.

Contextual Notes

There is an ongoing exploration of the definitions and implications of uncertainties in the context of the uncertainty principle, with some participants noting the need for clarification on how to calculate these uncertainties based on the provided information.

Andurien
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We have an electron pulse of width 1 nanosecond and with kinetic energy of 1keV. We have to calculate Δx and Δp.

I have a question regarding this problem. If they give us the kinetic energy of the electron pulse then we know exactly the momentum right? And so the uncertainty of momentum would be 0 and therefore Δx=∞ for the uncertainty principle ΔxΔp≥h. However I feel this reasoning is incorrect otherwise the problem would be trivial.
 
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The momentum, together with the energy, have some small uncertainty (<<1 keV). You can calculate the minimal uncertainty of this, based on the position uncertainty.
 
And how do I calculate the position uncertainty? Both Δx and Δ p are unkown.
 
Δx is known. It is hidden in the "length" of 1ns, and you can calculate the velocity.
 
Thank you I finally solved I didn't understand the meaning of that 1ns.
 

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