Problem dealing with a chapter on relativity

  • Thread starter Thread starter jrd007
  • Start date Start date
  • Tags Tags
    Relativity
Click For Summary

Homework Help Overview

The discussion revolves around a problem related to the concept of relativity, specifically focusing on length contraction as described by the Lorentz transformations. The original poster presents a scenario involving distances measured in light years from different reference frames.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between distance and velocity in the context of relativistic travel, questioning the definitions of light years and the application of Lorentz length contraction. There are attempts to clarify the proper use of formulas and the implications of different reference frames.

Discussion Status

Some participants have provided guidance on the correct application of the Lorentz contraction formula and have engaged in clarifying the definitions involved. There is an ongoing exploration of the necessary calculations to determine the speed required for the perceived distance to contract from 82 light years to 35 light years.

Contextual Notes

Participants are navigating potential confusion regarding the correct values to use in the formulas and the implications of different reference frames. There is a noted miscommunication regarding the use of specific distances in the calculations.

jrd007
Messages
159
Reaction score
0
I think I know how to do this problem, but need to make sure... so...

1) In an Earth reference frame, a star is 82 light years away. How fast would you have to travel so that to you the distance would only be 35 light years?

First I have two simple questions:

1. Light years is in a unit of time or length?

2. How to convert light years?

So I would use either:

a) L = Lo x sqroot(1-v^2/c^2) ~~~> 82 light years = 35 light years x sqr(1-v^2/(3.0 x 10^8)^2)

or

b) to = t x sqroot(1-v^2/c^2) ~~~> 35 light years = 85 light years x sqr(1-v^2/(3.0 x 10^8)^2)
 
Physics news on Phys.org
Light years is a unit of length, therefore, you would use Lorentz length contraction. A light year is the distance light can travel in the period of one year.

~H
 
A light year is a unit of length/distance.

If the distance between the Earth and the star (as seen from Earth) is 82 ly, how much of a contraction would be needed to make the distance only seem like 35 ly in the frame of someone traveling at relativistic velocities?

Lenth = Proper Length / gamma

where gamme is the lorentz factor,
gamma = 1/ sqrt(1 - v^2/c^2)

If we call "proper length" the length in the Earth's frame of reference, then we solve for gamma to be 82 ly / 35 ly = 2.3429

Now how fast must an object be flying fast Earth in order to have a lorentz factor this height?

2.3429 = 1/ sqrt(1 - v^2/c^2)
solve for v.
 
Last edited:
(also so you cannot use L = Lo x sqroot(1-v^2/c^2)?) Look below.

could you also have said --> 85 = 35 x sqroot(1-v^2/c^2) and then solve for V?
 
Last edited:
jrd007 said:
(also so you cannot use L = Lo x sqroot(1-v^2/c^2)?) Look below.

could you also have said --> 85 = 35 x sqroot(1-v^2/c^2) and then solve for V?

You have applied L = Lo x sqroot(1-v^2/c^2) here, which is the correct thing to do. However, I am confused as to why you have used 85 lightyears.

~H
 
I mis typed it the first time.
 
Then you are correct, apply lorentz's length contraction and solve for v.

~H
 

Similar threads

Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
734
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
15
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K