I've been stuck on this for ages and would appreciate help on how to do it:

On a train, the magnitude of the acceleration experienced by the passengers is limited to 0.050g.If the train is going round a curve at a speed of 220km/hr what's the smallest radius of curvature that the curve can have without exceeding the maximum allowed acceleration on the passengers.

Doc Al
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What have you done so far? Hint: What kind of acceleration is experienced when going around a curve?

so far i've attempted to solve using v=r w

Doc Al
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Here's another hint: What have you learned about centripetal acceleration?

em,in circular motion direction constantly changes.Centripetal acceleration is the resulting center directed acceleration.

Do I need the formula: a=v^2/r ?

Doc Al
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petal5 said:
Do I need the formula: a=v^2/r ?
Yes you do! When going around a curve, the acceleration is centripetal--that's what they are talking about in this problem.

Be sure to convert everything to standard units before calculating the radius.

Doc Al
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How did you arrive at that number?

I said 0.050g=v^2/r (taking v to be 61m/s)

Doc Al
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You are forgetting to divide by g, which equals 9.8 m/s^2.

Thanks for all your help!So should my equation be: v^2/r=(0.050)(9.80)

Doc Al
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That's right.

OlderDan