Problem understanding Thévenins equivalent circuit

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SUMMARY

The discussion centers on understanding Thévenin's equivalent circuit, specifically the calculation of the short-circuit current I(SC). Pellefant expresses confusion regarding the equation I(SC) = (B+E)I1/(C+B+E). A participant clarifies that to derive this equation, one must apply mesh analysis to the circuit, creating two mesh equations: one for the left loop with the voltage source and another for the right loop. By equating these equations, the voltage source can be eliminated, leading to the correct solution.

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Problem understanding "Thévenins equivalent circuit "

The problem is illustrated in the picture below.

http://img266.imageshack.us/img266/5422/thevininprobxn1.jpg

I am not sure i understand this so well either, any comments are appriciated.

Best regards

Pellefant
 
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Your answers are missing a factor of I1.

How did you get I(SC) = (B+E)I1/(C+B+E) ?

To get the answer just consider the mesh equation equations set up for the loop on the left with the voltage source, A and C in clockwise. Then, remembering that D is shorted, set up another mesh equation with the voltage source, A, B, E clockwise. Equate the two equations to eliminate the voltage source and you're done.
 

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