Problem with distance in relation to acceleration.

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SUMMARY

The discussion focuses on calculating the total distance traveled by a car during acceleration and deceleration phases. The car, weighing 1200 kg, accelerates to 14 m/s in 7 seconds, maintains that speed for 10 seconds, and then decelerates at -3.5 m/s². The key equations of motion, specifically the SUVAT equations, are essential for determining distance during acceleration and deceleration. The average speed during both phases is calculated to aid in finding the total distance.

PREREQUISITES
  • Understanding of basic physics concepts, specifically motion and acceleration.
  • Familiarity with the SUVAT equations of motion.
  • Ability to calculate average speed and apply it to distance formulas.
  • Knowledge of graphing speed versus time for motion analysis.
NEXT STEPS
  • Study the SUVAT equations in detail to understand their application in motion problems.
  • Learn how to calculate distance using average speed during different phases of motion.
  • Explore graphical representations of motion to visualize speed and distance relationships.
  • Practice similar physics problems involving acceleration and deceleration to reinforce concepts.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding motion dynamics, particularly in calculating distances during varying acceleration phases.

BeeGeeks
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Homework Statement
A 1200 kg car is at a red light on a horizontal road. When the road turns to green, (t0) he starts accelerating and reaches 14 m/s in 7 seconds. He then continues at a constant speed for 10 seconds, then brakes with a -3.5 m/s^2 acceleration.

All accelerations are assumed to be constant.

a) Calculate the amount of time he spends decelerating. (What I found through graphing : 4 seconds)

b) Graph the speed in relation to time starting with t0. (Done successfully)

c) Calculate the average speed in both the acceleration and deceleration phase. (7 m/s)<- this seems weird to me)

d) Calculate the total distance between the start of the acceleration until the final stop.

I'm having trouble with point d).

The problem

I don't understand how we can calculate a distance while the object is under acceleration. I can't wrap my head around it. Is there an equation I don't know about? Or am I overcomplicating things and it's just ( for this problem) an additional 2 meters per second during the acceleration phase, then 10 seconds of adding 14 m per second and then decreasing the number you add to your total by 3 every second starting by 14 during your deceleration? is it that obvious?

Thanks in advance!
 
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BeeGeeks said:
I don't understand how we can calculate a distance while the object is under acceleration.
Why not? It's moving isn't it? What's the average speed during each segment of the motion? Use that to find the distance traveled.
 
Doc Al said:
Why not? It's moving isn't it? What's the average speed during each segment of the motion? Use that to find the distance traveled.

Thanks!
 

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