Projectile A - > B , two different angles

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The discussion focuses on determining the launch angles, theta 1 and theta 2, for projectiles fired from point A to point B, which is elevated at a height H and a horizontal distance L. The key equations involve the vertical and horizontal motion of the projectiles, leading to relationships between the angles and their respective times of flight. The user initially struggles to isolate variables but later derives a quadratic equation in terms of tan(theta), indicating progress in the problem-solving process. The complexity of the quadratic suggests that it may be solvable, though further assistance is sought to clarify the approach. The conversation emphasizes the mathematical relationships governing projectile motion in different trajectories.
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Homework Statement


Muzzle velocity at A = Vo. Determine the two angles, theta 1 and theta 2.

A is separated from B by a distance L in the x direction and a height H. (B is on a hill above A).

Homework Equations





The Attempt at a Solution


I feel that the important facts of this problem is that sin(theta1)Vo * t1 - gt1^2 = sin ( theta2 )Vo * t2 - gt2^2, since the y displacement for both projectiles are identical. Similarly, we have that the x projectiles are the same, so that cos (theta1 )Vo * t1 = cos ( theta 2 )Vo * t2.
With these equations, I have two variables two equations, but I cannot figure out how/if it is possible to solve these to isolate a variable. I am guessing that there is probably an easier way to do this, so a small hint would be greatly appreciated!

thanks guys.
 
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Actually, after a bit more working through, I came up with a quadratic in terms of tan ( theta ) . The equation itself looks pretty nasty, but does this make sense? I have a tan^2, Tan, and then a constant, so it seems like it could definelty be a quadratic.

Any input apprecaited.
 
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