Projectile A - > B , two different angles

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SUMMARY

The discussion focuses on determining the two launch angles, theta 1 and theta 2, required for a projectile to travel from point A to point B, given a horizontal distance L and a vertical height H. The key equations derived include the vertical displacement equation sin(theta1)Vo * t1 - gt1^2 = sin(theta2)Vo * t2 - gt2^2 and the horizontal displacement equation cos(theta1)Vo * t1 = cos(theta2)Vo * t2. The user successfully reformulated the problem into a quadratic equation involving tan(theta), indicating a clear path to finding the angles. This approach confirms the feasibility of solving for the angles using trigonometric identities and projectile motion principles.

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Homework Statement


Muzzle velocity at A = Vo. Determine the two angles, theta 1 and theta 2.

A is separated from B by a distance L in the x direction and a height H. (B is on a hill above A).

Homework Equations





The Attempt at a Solution


I feel that the important facts of this problem is that sin(theta1)Vo * t1 - gt1^2 = sin ( theta2 )Vo * t2 - gt2^2, since the y displacement for both projectiles are identical. Similarly, we have that the x projectiles are the same, so that cos (theta1 )Vo * t1 = cos ( theta 2 )Vo * t2.
With these equations, I have two variables two equations, but I cannot figure out how/if it is possible to solve these to isolate a variable. I am guessing that there is probably an easier way to do this, so a small hint would be greatly appreciated!

thanks guys.
 
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Actually, after a bit more working through, I came up with a quadratic in terms of tan ( theta ) . The equation itself looks pretty nasty, but does this make sense? I have a tan^2, Tan, and then a constant, so it seems like it could definelty be a quadratic.

Any input apprecaited.
 

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