Projectile Motion Bullet Shot Help

AI Thread Summary
The discussion focuses on solving a projectile motion problem involving a bullet shot horizontally at 300 m/s and its shell casing falling vertically with a velocity of 5 m/s. Participants emphasize the need to separate the problem into horizontal and vertical components, using kinematic equations to find the bullet's travel distance and its vertical velocity just before hitting the ground. Key equations mentioned include those for horizontal distance (Δx) and vertical motion (vfy). The importance of calculating the time of fall based on the shell's vertical velocity is also highlighted. Understanding these components is crucial for determining the bullet's range and vertical velocity at impact.
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Homework Statement

bullet shot horizontally over level ground with a velocity of 300m/s. at the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00m/s

how far does the bullet travel

what is the vertical component of the bullet's velocity at the instant before it his the ground?
I tried a bunch of stuff and I didnt get the right answer, can someone just point me in the right direction? Please, at least tell me which equation to use cause I can't figure this out.
 
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yogoes123 said:
bullet shot horizontally over level ground with a velocity of 300m/s. at the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00m/s
Hi yogoes123. Is there a question attached to this statement?
 
sorry i somehow missed that, very sorry i edited it.
 
yogoes123 said:
I tried a bunch of stuff and I didnt get the right answer, can someone just point me in the right direction? Please, at least tell me which equation to use cause I can't figure this out.
Same here. I can't figure out which equation to use until I have condensed that wordy statement into something that looks more mathematical.

First thing, write down all the information that you know, expressing it as values of variables, e.g.,

bullet: vi = 300 m/sec

casing: vi = ?
    vf = ?

etc.
 
what is distance d of fall given time of fall T?
what is velocity of fall, given time of fall T?
 
Ok guys i think there is a bit of confusion. The question says the bullet has a horizontal velocity of 300 m/s.

They want you to find range.

They also say the bullet shell falls vertically at a rate of 5 m/s, not sure why but its probably needed.

Thats all they give u.

Horizontal Velocity of bullet: 300 m/s

Vertical velocity of SHELL: 5m/s
 
You need to quote the actual problem verbatim for us. The casing will not fall with uniform velocity.
 
A sharpshooter shoots a bullet horizontally over level ground with a velocity of 3.00 x 10^2 m/s. At the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00 m/s

a) How far does the bullet travel

b) What is the vertical component of the bullet's velocity at the instant before it hits the ground.
 
yogoes123 said:

Homework Statement




bullet shot horizontally over level ground with a velocity of 300m/s. at the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5.00m/s. So if you want to find the distance it traveled, you need to find ow far it traveled in x and in y.

how far does the bullet travel

what is the vertical component of the bullet's velocity at the instant before it his the ground?



I tried a bunch of stuff and I didnt get the right answer, can someone just point me in the right direction? Please, at least tell me which equation to use cause I can't figure this out.

Break this down into your knowns and unknowns.

You only have four kinematic equations.

U1L6a1.gif


This problem is a projectile problem that is asking you to break things up in terms of x and y. First the shell moves initially with the bullet at 300 m/s horizontally, and then when it approaches 0 m/s, due to gravity it accelerates vertically at 9.8 m/s2 towards the Earth to reach a final velocity of 5 m/s.

So what do you know?

Horizontal Movement

Vix= 300 m/s
t=(5m/s)/(9.8m/s2)=0.5097s
ax= 0 m/s2
Δx=?

Δx=(vix)(t) + (0.5)(ax)(t)2

Vertical Movement

viy= 0 m/s
vfy= 5m/s
ay= 9.8 m/s2
Δx=?

vfy2 = viy2 + (2)(ay)(Δy)
 
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