(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In fighting forest fires, airplanes work in support of ground crews by dropping water on the fires. A pilot is practicing by dropping a canister of red dye, hoping to hit a target on the ground below.

if the plane is flying in a horizontal path at an altitude of 86.0 m above the ground and with a speed of 69.0 m/s, at what horizontal distance from the target should the pilot release the canister? Ignore air resistance.

2. Relevant equations

Any constant acceleration equation.

3. The attempt at a solution

ax=0

ay=-9.80

Xo= 0

Yo=86.0

Voy=0

Vox= 69.0

Vx=69.0

Vy=

y=0

x=

I first found T_{total}by using the equation 0-86.0=0+.5(-9.80)(t^2).

t = 4.189 seconds.

then I found Vy.

Vy= 0+(-9.8)(4.189)

Vy= -41.052

Then I realized finding Vy was a complete waste of time. ¯\_(ツ)_/¯

Then I tried to find x.

x-0 = (69.0)(4.189)+.5(-9.8)(4.189)^2

x = 203.05 m/s?

Does this look right?

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# Projectile motion firehose question

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