Projectile motion firehose question

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SUMMARY

The discussion focuses on calculating the horizontal distance from a target at which a pilot should release a canister while flying at an altitude of 86.0 m and a speed of 69.0 m/s. The pilot first determined the total time of flight (Ttotal) to be 4.189 seconds using the equation for vertical motion under constant acceleration. The horizontal distance (x) was then calculated using the formula x = Vox * Ttotal, but the participant initially included an incorrect acceleration term in their calculations. The correct horizontal distance to release the canister is approximately 203.05 meters.

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Crusaderking1
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Homework Statement



In fighting forest fires, airplanes work in support of ground crews by dropping water on the fires. A pilot is practicing by dropping a canister of red dye, hoping to hit a target on the ground below.

if the plane is flying in a horizontal path at an altitude of 86.0 m above the ground and with a speed of 69.0 m/s, at what horizontal distance from the target should the pilot release the canister? Ignore air resistance.

Homework Equations



Any constant acceleration equation.

The Attempt at a Solution



ax=0
ay=-9.80

Xo= 0
Yo=86.0

Voy=0
Vox= 69.0

Vx=69.0
Vy=

y=0
x=

I first found Ttotal by using the equation 0-86.0=0+.5(-9.80)(t^2).

t = 4.189 seconds.

then I found Vy.

Vy= 0+(-9.8)(4.189)

Vy= -41.052

Then I realized finding Vy was a complete waste of time. ¯\_(ツ)_/¯

Then I tried to find x.

x-0 = (69.0)(4.189)+.5(-9.8)(4.189)^2

x = 203.05 m/s?

Does this look right?
 
Last edited:
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You are right down to where you found T total. In your last equation where you are calculating the value for x, you use an acceleration of -9.8. What is the acceleration along the x axis?(hint, you answered this when you state your value for ax.)
 
bacon said:
You are right down to where you found T total. In your last equation where you are calculating the value for x, you use an acceleration of -9.8. What is the acceleration along the x axis?(hint, you answered this when you state your value for ax.)

Oh, thanks for the catch, I really appreciate it!
 

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