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I'm sure you get a lot of projectile motion questions on here, sorry bout this. I used the search feature but I couldn't find anything quite like this problem and it's giving me some issues. It just doesn't seem like they give enough information for solving!

A golfer can hit a golf ball a horizontal distance of over 300m on a good drive. What maximum height would a 301.5m drive reach if it were launched at an angle of 25.0 degrees to the ground.

Theta = 25 degrees

Distance (x) = 301.5m

At max height, Velocity (y) = 0

Max height is at 1/2t

D(x) = Vi*(cos25)*t

V(x) = Vi*(cos25)

D(y)= Vi*(sin25)*t - .5*g*t^2

V(y), f = Vi*(sin25) - g*t

(Vy, f) ^2 = (Vi)^2*(sin25)^2 - 2g*D(y)

I tried this problem for at least 45 minutes, but each time I just ended up erasing everything because it wouldn't work out. I was trying to work out the initial velocity, but I kept getting 2 unknowns in all the equations! Thanks for helping me :)

**1. Homework Statement**A golfer can hit a golf ball a horizontal distance of over 300m on a good drive. What maximum height would a 301.5m drive reach if it were launched at an angle of 25.0 degrees to the ground.

Theta = 25 degrees

Distance (x) = 301.5m

At max height, Velocity (y) = 0

Max height is at 1/2t

**2. Homework Equations**D(x) = Vi*(cos25)*t

V(x) = Vi*(cos25)

D(y)= Vi*(sin25)*t - .5*g*t^2

V(y), f = Vi*(sin25) - g*t

(Vy, f) ^2 = (Vi)^2*(sin25)^2 - 2g*D(y)

**3. The Attempt at a Solution**I tried this problem for at least 45 minutes, but each time I just ended up erasing everything because it wouldn't work out. I was trying to work out the initial velocity, but I kept getting 2 unknowns in all the equations! Thanks for helping me :)

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