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Projectile Motion Golf Question

  1. Jul 5, 2011 #1
    1. The problem statement, all variables and given/known data
    Not too long ago, an interesting thing happened at the Canadian Open Golf Tournament. Tiger Woods bounced his tee shot off of a young spectator’s head in the last round of the tournament. The ball made contact for 0.08 seconds, and struck the boy’s head at a velocity of 32 m/s, 25degree from a tangent on the surface of his cranium. It bounced off at an angle of 22degree, with a speed of 25 m/s. What was the average acceleration of the ball as it amazingly made its way back onto the fairway?

    I have no idea on how to start this.


    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jul 5, 2011 #2

    ideasrule

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    What's the difference between the final velocity of the ball and its initial velocity? Remember that acceleration is just change in velocity divided by change in time.
     
  4. Jul 5, 2011 #3

    Delphi51

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    Welcome to PF, Michael.
    Not a particularly clear question! I would be tempted to answer that the acceleration is -9.81 m/s² as it "makes its way back onto the fairway" but I suppose the question really means the acceleration while in contact with the boy's head. There are 2D directions involved so you need a diagram sorting out those angles and you need to calculate the acceleration in each of the two dimensions and then get a combined value. Just use a = Δv/Δt.
     
  5. Jul 5, 2011 #4
    I thought in projectile motion, the horizontal velocity does not change, thus a = 0 and its 9.81 for the vertical component?
     
  6. Jul 6, 2011 #5

    Delphi51

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    That's true for the free flight (neglecting air resistance).
    But my theory is that you are asked for the acceleration when the head is exerting a force on the ball. I haven't drawn the diagram, but since the angle with the head changes, I suspect the ball changes speed in both the direction perpendicular to the head and the direction parallel to it.
     
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