Projectile Motion Help - Find Angle of Elevation for Rajesh

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Rajesh is seeking assistance with calculating the angle of elevation for a projectile motion problem, given a launch point higher than the target, a specified speed range, and a destination point. He expresses difficulty in understanding the mathematical concepts involved and has received links to resources but remains confused. Respondents suggest breaking the problem into x and y components of motion, using constant acceleration equations to derive the angle. They recommend eliminating time from the equations to find a single equation for the angle of elevation. The discussion emphasizes the importance of understanding the physics principles behind projectile motion to solve the problem effectively.
rajesh.msen
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Hi to all,
I have a problem in projectile motion.I need the angle of elevation.I know the launch point its greater than the target,I know the destination point where it should land,i know the speed it travels(its option for users to select the speed between (60 - 100),I need the angle of elevation to reach the destination point.
Ex : Angle of elevation differs based on the value of the variable speed.I not good in maths and very new to physics.Any one help me to solve this problem.Even tell me if the solution is not exit.
Help me guys.Thanks in advance.


---Rajesh---

Homework Statement


velocity,launch_point,landing_point


Homework Equations





The Attempt at a Solution

 
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Welcome to PF!

Hi Rajesh! Welcome to PF! :wink:

Write equations for the x and y components separately.

For x, remember that the x component of velocity is constant.

For y, use the standard constant acceleration equations. :smile:
 
Hi Rajesh! :smile:

(btw, no need to PM me … everyone gets automatic email notification of any reply to a thread that they've contributed to :wink:)

The question gives you vi (but not its direction), and x and y.

So call the time t, and call the direction θ, so that the initial components of velocity are vicosθ horizontally and visinθ vertically.

Then use the standard constant acceleration equations for the horizontal direction (a = 0) and the vertical direction (a = -g) separately: that gives you two equations, from which you can eliminate t, so you get one equation for θ. :smile:
 
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