Projectile Motion Help: Finding Time, Angle, and Velocity

AI Thread Summary
To solve the projectile motion problem, the key is to focus on the vertical motion since no horizontal information is provided. The initial height is 1.02m, the maximum height is 1.85m, and the final height is 0.93m. Time of flight can be calculated using the equations of motion that relate distance, gravity, and time, specifically V = Vi + at and d = di + Vi*t + 0.5*a*t^2. Without a specified launch angle, the horizontal velocity remains indeterminate. Understanding these vertical motion equations is crucial for finding the necessary parameters.
pberardi
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Homework Statement



Help with projectile motion please?
A particle is at an elevation of 1.02m from the floor when it takes off. It reaches a max height of 1.85m above the floor and stops at .930m above the floor. How do you find the time of flight, the take off angle, the initial vertical and horizontal velocity?

Homework Equations





The Attempt at a Solution



I have no idea how to start this without a given angle. Can someone explain this concept to me?
 
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pberardi said:
A particle is at an elevation of 1.02m from the floor when it takes off. It reaches a max height of 1.85m above the floor and stops at .930m above the floor. How do you find the time of flight, the take off angle, the initial vertical and horizontal velocity?

I have no idea how to start this without a given angle. Can someone explain this concept to me?

All the info given is vertical. So I don't see any way to address any horizontal or angle of launch issues.

For the time, you can figure that by relating distance gravity and time.

Here are some equations:
https://www.physicsforums.com/showpost.php?p=905663&postcount=2
 
No horizontal information is given, so the horizontal velocity could be anything!
The vertical part can be worked out with the usual formulas V = Vi + at and d = di + Vi*t + .5*a*t^2 for accelerated motion. Or even more easily with that formula that has no t in it.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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