Projectile Motion in Combination with Energy Problem

AI Thread Summary
To solve the problem of hitting a target 15m away with a toy rifle using a spring, the initial velocity must be determined using the horizontal range formula for projectile motion. The spring's potential energy can be equated to the kinetic energy needed to achieve this velocity. The relevant equations include E = 1/2(k)(x)² for potential energy and KE = 1/2(m)(v)² for kinetic energy. By calculating the necessary initial velocity, the required compression of the spring can then be found. This approach effectively combines principles of projectile motion and energy conservation.
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Homework Statement


A toy rifle shoots a spring of mass 0.008kg and with a spring constant of 350 N/m. You wish to hit a target horizontally a distance of 15m away by pointing the rifle 45o above the horizontal. How far should you extend the spring in order to reach the target?


Homework Equations


E = 1/2(k)(x)2
F = kx
KE = 1/2(m)(v)2
Any relevant kinematics formulae.


The Attempt at a Solution


Normally for questions like this I would equate potential spring energy to the kinetic energy, but here I am missing a velocity as well as the spring compression length so I am a little lost.
 
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Bound said:

Homework Statement


A toy rifle shoots a spring of mass 0.008kg and with a spring constant of 350 N/m. You wish to hit a target horizontally a distance of 15m away by pointing the rifle 45o above the horizontal. How far should you extend the spring in order to reach the target?


Homework Equations


E = 1/2(k)(x)2
F = kx
KE = 1/2(m)(v)2
Any relevant kinematics formulae.


The Attempt at a Solution


Normally for questions like this I would equate potential spring energy to the kinetic energy, but here I am missing a velocity as well as the spring compression length so I am a little lost.
Use the formula for horizontal range for projectile motion letting sin2θ = 1 and R = 15 m. to determine the initial velocity v that is needed. From that you can work out the kinetic energy and, therefore, the potential energy of the spring.

AM
 
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