Projectile Motion Long Jump Help

AI Thread Summary
The discussion focuses on solving a projectile motion problem related to long jump performance. The athlete's takeoff angle is 30 degrees, and they travel a distance of 7.80 meters. Participants are seeking assistance with calculating the takeoff speed and the impact of a 5% increase in speed on jump distance. There are challenges in determining the time of flight and initial velocity using various equations. The thread highlights the need for clarity in applying projectile motion formulas to solve these types of problems effectively.
singlish
Messages
1
Reaction score
0
An athlete executing a long jump leaves the ground at a 30 degree angle and travels 7.80m.
(a). What was the takeoff speed?
(b). If this speed were increased by just 5.0 percent, how much longer would the jump be?

I'm having some troubles with part a. I've been struggling to comprehend projectile motion and I've been trying to find T using different methods but none of them work. I eventually came up with 9s using cosine, but I can't find initial velocity now. Any advice or tips would be appreciated.
 
Physics news on Phys.org
x=(ucos30)t
t=2usin30/g
R=(u^2sin(2*30))/g
 
guys.. can you please help me with this simple problem my instructors gave us for home work... its about projectile motion..

what is the time if the displacement is at 21 meters having a 35degrees angle with the original velocity of 100m/s.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top