Projectile Motion Problem: Finding Minimum Jumping Speed of a Salmon

AI Thread Summary
To determine the minimum jumping speed of a salmon at a 32.0° angle to clear a 0.55m waterfall while starting 2.00m away, the problem involves breaking the velocity into horizontal and vertical components. The horizontal motion is described by Δx = vi(cosθ)Δt, while the vertical motion is governed by Δy = vi(sinθ)Δt - 1/2g(Δt)². By expressing Δt from the horizontal equation and substituting it into the vertical equation, the initial speed can be calculated. Understanding vector operations is crucial, as the salmon's velocity has both forward and upward components. The solution requires applying these principles to find the necessary initial speed for the jump.
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Homework Statement



starting at 2.00m away from a waterfall .55m in height, at what minimum speed must a salmon jumping at an angle of 32.0° leave the water to continue upstream?

Homework Equations



Δx=vi(cosθ)Δt
Δy=vi(sinθ)Δt-1/2g(Δt)2

The Attempt at a Solution



there were some other equations in the book, but i just can't make the connection, i know i can find vx,i and vy,i if i had vi but i don't know any velocities. i tried using cos32°=(2.0m/h) but i can't get any further, so little help would be appreciated. also i am new.

Homework Statement


Homework Equations


The Attempt at a Solution

 
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From the first equation, you can express Δt (unknown) in terms of everything else in it.

You can plug that Δt into the second equation, thus getting an equation for the unknown initial speed.
 
starting at 2.00m away from a waterfall .55m in height, at what minimum speed must a salmon jumping at an angle of 32.0° leave the water to continue upstream?
..........

First you have to know about vector operation.
\vec{A}=\vec{B}+\vec{C}

You have to think of the reversal.
The salmon is jumping at minimum speed with 32.0° angle.
So will call this velocity \vec{A}

Thus \vec{A} has 2 components \vec{B} which say in forward direction and \vec{C} in upward direction.

Horizontal velocity is constant.
Vertical motion is affected by gravity.
 
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