Projectile Motion: Calculating Parcel Time and Car Speed

In summary, the parcel falls 1.5m in the vertical direction with an initial velocity of 0, using the equation d=v1*t+(1/2)at^2. The horizontal velocity of the parcel can then be calculated using the time found and the distance of 12m. The speed of the car before colliding with the wall was not provided in the conversation.
  • #1
whitestrat69
12
0

Homework Statement


A car collides with a brick wall and comes to rest.
A parcel which was on top of the roof at the time becomes detached. It is initially traveling horizontally and it strikes the ground a distance of 12m from the point where it left the car. The parcel is initially 1.5 m above ground.

What period of time elapses before the parcel strikes the ground?

Estimate the speed of the car just before it collided with the wall?

Homework Equations


s=ut+1/2at^2
v=u+at
v^2=u^2+2as

The Attempt at a Solution


i have no idea where to start, ??
 
Last edited:
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  • #2
You need the velocity with which the car collided?

How long does it take the parcel to fall 1.5m?

Use this time with the 12m to get the horizontal velocity.
 
  • #3
yes, that's what i initially thought as iv'e tried working this out... the velocity was not provided..?
 
  • #4
whitestrat69 said:
yes, that's what i initially thought as iv'e tried working this out... the velocity was not provided..?

can you show your steps? what was the answer given?
 
  • #5
no it wasnt, i haven't made any sufficient steps..
 
  • #6
whitestrat69 said:
no it wasnt, i haven't made any sufficient steps..

First step, find the time it takes to drop 1.5m.

this is the vertical direction. initial vertical velocity = 0

try to apply:

d = v1*t + (1/2)at^2

to this situation.
 
  • #7
thankyou!:smile:
 
  • #8
whitestrat69 said:
thankyou!:smile:

no prob.
 

1. How do you calculate the maximum height of a projectile?

The maximum height of a projectile can be calculated using the formula h = (v2sin2θ)/2g, where v is the initial velocity, θ is the angle of launch, and g is the acceleration due to gravity.

2. What is the equation for the range of a projectile?

The equation for the range of a projectile is R = (v2sin2θ)/g, where v is the initial velocity, θ is the angle of launch, and g is the acceleration due to gravity.

3. How does air resistance affect projectile motion?

Air resistance can decrease the distance and height of a projectile by exerting a force in the opposite direction of its motion. This force increases as the velocity and surface area of the projectile increase, and can greatly impact the trajectory of the projectile.

4. Can a projectile have a negative velocity?

Yes, a projectile can have a negative velocity if it is launched at an angle below the horizontal line. This means that the projectile is moving downwards at some point during its trajectory.

5. How does changing the angle of launch affect the distance of a projectile?

Changing the angle of launch can greatly affect the distance of a projectile. The maximum distance is achieved when the angle is 45 degrees, and any angle above or below this will result in a shorter distance. This is because the vertical and horizontal components of the initial velocity are equal at 45 degrees, allowing the projectile to travel the furthest.

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