How Does an Object's Trajectory Intersect with a Sloped Line?

In summary, the problem involves an object being launched at an initial velocity and at an angle above a straight line, with the line itself at an angle above the horizontal. The goal is to find at what point the object intersects with the line, given the variables v, alpha, theta, and g. The relevant equations involve vertical and horizontal displacement, and the solution requires setting these equations equal to each other and resolving acceleration due to gravity in new axes.
  • #1
grinosaurus
1
0
Hello happy online physics homework helpers! Long time listener, first time caller. Had a test today, and was stumped by a question about projectile motion - it's in the past now but I'd still like to figure it out. And - in the interest of full disclosure - I think we can do some corrections of out test to get a quarter of the marks missed.

Anyways, I'll be describing it from memory and it was originally drawn out... so hopefully this is coherent and correct.

Homework Statement



An object is launched into the air at initial velocity v, in a direction that is alpha degrees above a straight line (l). This line, in turn, is theta degrees above the horizontal. At what point does the object intersect with line l - your answer should be given in terms of v, alpha, theta and g.


Homework Equations



well,

vertical displacement = sin(α + θ)*t - g/2(t^2)
hortizontal displacement = cos(α + θ)*t

other than that, I'm really stumped.

The Attempt at a Solution



I know you guys are are sticklers for this, but I am quite bamboozled. Can I say that the slope of the straight line is tanθ, so it's equation is y=tanθ*x, then set equal to something?

Sheesh.

Thanks in advance!
 
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  • #2
grinosaurus said:
Hello happy online physics homework helpers! Long time listener, first time caller. Had a test today, and was stumped by a question about projectile motion - it's in the past now but I'd still like to figure it out. And - in the interest of full disclosure - I think we can do some corrections of out test to get a quarter of the marks missed.

Anyways, I'll be describing it from memory and it was originally drawn out... so hopefully this is coherent and correct.

Homework Statement



An object is launched into the air at initial velocity v, in a direction that is alpha degrees above a straight line (l). This line, in turn, is theta degrees above the horizontal. At what point does the object intersect with line l - your answer should be given in terms of v, alpha, theta and g.

Homework Equations



well,

vertical displacement = sin(α + θ)*t - g/2(t^2)
hortizontal displacement = cos(α + θ)*t

other than that, I'm really stumped.

The Attempt at a Solution



I know you guys are are sticklers for this, but I am quite bamboozled. Can I say that the slope of the straight line is tanθ, so it's equation is y=tanθ*x, then set equal to something?

Sheesh.

Thanks in advance!
[tex]x_{v}(t) = sin(\alpha + \theta)vt - \frac{gt^2}{2}[/tex]
[tex]x_{vL}(t) = x_{h}(t)tan(\theta)[/tex]

where x(t) is a function of displacement relative to the tossing point, the subscript h means horizontal, the subscript v means vertical, and the subscript L means 'for the line' (as opposed to 'for the tossed object')

You are interested in finding when these two equations equal each other. Note, the height for the line is its slope (y/x) times how much x it has displaced, which is always equal to how much x the tossed object has displaced.
 
  • #3
the best and most efficient way is to take x-axis along the given line. In this way you will have to resolve acceleration due to gravity in these new axes. Not much complication in this way I hope...
 
  • #4
yeah...forgot something, here displacement in y is zero - no problem at all now huh? enjoy
 
  • #5


Hello! Thank you for reaching out to us for help with your physics question about projectile motion. I'm sorry to hear that you were stumped on this question during your test, but I'm glad you're still interested in figuring it out.

Based on the information you provided, it seems like you're on the right track with your equations for vertical and horizontal displacement. To find the point of intersection with the line l, you will need to set the vertical displacement equal to the horizontal displacement and solve for t. This will give you the time at which the object intersects with the line.

As for the slope of the line, you are correct that it is equal to tanθ. This information can be useful in solving the equation for t.

I hope this helps guide you in the right direction. Remember to always carefully read the question and identify the relevant equations and variables before attempting a solution. Good luck!
 

1. What is projectile motion?

Projectile motion is the motion of an object through the air or space under the influence of gravity. It follows a curved path known as a parabola.

2. What factors affect projectile motion?

The factors that affect projectile motion include the initial velocity, angle of launch, air resistance, and gravity.

3. What is the formula for calculating projectile motion?

The formula for calculating projectile motion is:
Horizontal distance = initial velocity x time x cosine of launch angle
Vertical distance = initial velocity x time x sine of launch angle - 1/2 x gravity x time^2

4. Can the angle of launch affect the range of a projectile?

Yes, the angle of launch can significantly affect the range of a projectile. A higher angle of launch will result in a longer range, while a lower angle will result in a shorter range.

5. What is the maximum height a projectile can reach?

The maximum height a projectile can reach is at the peak of its trajectory. This can be calculated using the formula:
Maximum height = (initial velocity x sine of launch angle)^2 / (2 x gravity)

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