Projectile motion snowball help

AI Thread Summary
A snowball rolls off a barn roof at a height of 14 m and strikes the ground after traveling horizontally 11.792 m from the edge, calculated using projectile motion equations. The horizontal velocity is determined to be 5.36 m/s, while the vertical motion considers gravity's effect, leading to a time of 2.2 seconds before impact. For the second part of the problem, to determine if a man standing 4 m away will be hit, the vertical displacement at that time must be calculated. The initial vertical velocity should be negative due to downward motion, and the height of the snowball at 4 m horizontal distance must be compared to the man's height of 1.9 m. The discussion emphasizes the importance of correctly defining the coordinate system for accurate calculations.
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[SOLVED] Projectile motion help

A snowball rolls of a barn roof that slopes downward at an angle of 40 degrees. The edge of the roof is 14 m above the ground, and the snowball has a speed of 7 m/s as it rolls off the roof.

a) How far from the edge of the barn does the snowball strike the ground if it doesn't strike anything else while falling?

b) A man 1.9 m tall is standing 4 m from the edge of the barn, will he be hit by the snowball?

My answer is 11.792 m for (a)

x
a=0
v=7cos40=5.36
x=5.36t


y
a=-9.8
v=7sin40-9.8t= 4.5-9.8t
y=4.5t-4.9t^2+14 (is this right?)

When y=0 : 0=-4.9t^2 + 4.5t + 14 (use quadratic equation)
t=2.2
Plug it into x equation: x=5.36(2.2)
x=11.792 m

Now for (b) i don't know what to do. I said x=4 and got t=.746 s
Then I plugged it into the y equation but my answer turned out to be 14.36 which is impossible. Any help is greatly appreciated.
 
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Your equation for x-axis is correct. However, in the equations along y axis, the initial velocity should be with -ve sign (-4.5 m/s) because it is downward (same reason acceleration g is -ve). As the snowball hits the ground, vertical displacement is -14m (note the -ve sign). Put y=-14 in the second equation and solve for t. Put this value of t in the equation for x to obtain the required distance from the edge of the barn.

To find answer to b) : Determine the time instant when horizontal displacement is 4m. Then determine the vertical displacement (from the top) at that instant. Determine height of the snowball from ground. That will answer b).
 
Vijay Bhatnagar said:
Your equation for x-axis is correct. However, in the equations along y axis, the initial velocity should be with -ve sign (-4.5 m/s) because it is downward (same reason acceleration g is -ve). As the snowball hits the ground, vertical displacement is -14m (note the -ve sign). Put y=-14 in the second equation and solve for t. Put this value of t in the equation for x to obtain the required distance from the edge of the barn.

To find answer to b) : Determine the time instant when horizontal displacement is 4m. Then determine the vertical displacement (from the top) at that instant. Determine height of the snowball from ground. That will answer b).

Thank you but shouldn't y still equal zero because the y and x-axis is on the bottom of the barn not the roof; even though its traveling negative it hits at zero, not -14?

Never mind, its the same thing. Thank you so much!
 
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The choice of the origin is optional. You could take the top point as y=0 or the ground as y=0. In the first case initial displacement will be 0 and final displacement -14m. In the second case initial and final displacements will be +14m and 0 respectively. All equations for y-axis will written accordingly.
 
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