Projectile Motion, With out numbers

AI Thread Summary
A body projected at an angle has a horizontal range equal to three times its maximum height. To solve for the angle of projection, the relationship R = 3h can be established using the formulas for horizontal range (R) and maximum height (h). The discussion emphasizes breaking the problem into components, using the equations for horizontal and vertical motion. The final calculated angle of projection is 53.13 degrees. Understanding these concepts is crucial for solving projectile motion problems effectively.
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Projectile Motion, With out numbers :(

Homework Statement



A body is projected at an angle such that the horizontal range is equal to three times the greatest height. find the angle of projection.

Homework Equations


I don't know


The Attempt at a Solution



all i got so far is that vx= v cos(angle) and vy= v sin(angle)

This is a really tricky question for me and i do not know where to start.
 
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You should be able to look in your text for formulas for horizontal range (R) and max height (h). Use thes formulas to write R = 3 h, and then solve for projection angle theta.

If you don't have these formulas, the problem is a bit longer...
 


Split in into components. x(t)=vx*t, y(t)=vy*t-(1/2)*g*t^2. Find the range by figuring out when y(t)=0. The height is where y(t) is a maximum. Where is that?
 


ah. i got it. thanks so much. my final answer was 53.13 degrees.
 
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