# Projectile motion

1. Sep 25, 2007

### texmex

A projectile is to be fired so that it just clears an obstacle 80m high at its maximum height.

a) by considering the vertical motion only, calculate the verticle speedand the time taken to reach its maximum height
b) if the distance between A to B is 100m, calculate the horizontal speed with wich the ball was thrown.
c) Hence find v and Θ.

totally stuck at this, any help much appricated.

2. Sep 25, 2007

### hage567

Have you tried anything? What equations might be used? What can you say about the vertical component of the velocity at maximum height?

3. Sep 25, 2007

### texmex

the farthest i got, was putting in the right angle, and as for equations that could be used, i think it may have something to do with - Vvertical= vsinΘ. not entirely sure though.

4. Sep 25, 2007

### hage567

That would be the initial vertical velocity (is that a negative sign?). What is the vertical velocity at the instant of maximum height?

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