Projectile Motion

1. Jan 22, 2008

Bingo1915

1. A projectile is launched at 10 m/s
from a sloping surface. The angle $$\alpha=80 deg$$. Determine the range R.

2. Attached is the drawing.

3. Treat as 2 equations.

x-direction

Initial time t=0 Initial V$$_{x}$$=V$$_{0}$$Cos$$\theta$$

a$$_{x}$$dv$$_{}x$$/dt = 0

V$$_{x}$$=Initial VCos$$\theta$$ = dx/dt

Integrate and get
x=Initial V(Cos$$\theta$$)(t)
x=10(Cos80)(t)

Y-direction

a$$_{}y$$=-9.81 m/ss

V$$_{}y$$=-10Sin80

Im not sure if Im using the correct angle for theta (80 or 50) and Im stuck on the y-direction.
Can you help?

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2. Jan 23, 2008

physixguru

never integrate projectile equations is all that what i will tell ya...

think differently....

3. Jan 23, 2008

andrevdh

What you can try is develop the kinematic equations normal to and along the slope. The accelerations are the components of g in the respective directions. You then set the normal position coordinate to zero as a condition to find the range .