# Projectile Motion

1. Jan 22, 2008

### Bingo1915

1. A projectile is launched at 10 m/s
from a sloping surface. The angle $$\alpha=80 deg$$. Determine the range R.

2. Attached is the drawing.

3. Treat as 2 equations.

x-direction

Initial time t=0 Initial V$$_{x}$$=V$$_{0}$$Cos$$\theta$$

a$$_{x}$$dv$$_{}x$$/dt = 0

V$$_{x}$$=Initial VCos$$\theta$$ = dx/dt

Integrate and get
x=Initial V(Cos$$\theta$$)(t)
x=10(Cos80)(t)

Y-direction

a$$_{}y$$=-9.81 m/ss

V$$_{}y$$=-10Sin80

Im not sure if Im using the correct angle for theta (80 or 50) and Im stuck on the y-direction.
Can you help?

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2. Jan 23, 2008

### physixguru

never integrate projectile equations is all that what i will tell ya...

think differently....

3. Jan 23, 2008

### andrevdh

What you can try is develop the kinematic equations normal to and along the slope. The accelerations are the components of g in the respective directions. You then set the normal position coordinate to zero as a condition to find the range .

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