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Projectile Motion

  1. Jan 22, 2008 #1
    1. A projectile is launched at 10 m/s
    from a sloping surface. The angle [tex]\alpha=80 deg[/tex]. Determine the range R.

    2. Attached is the drawing.


    3. Treat as 2 equations.

    x-direction

    Initial time t=0 Initial V[tex]_{x}[/tex]=V[tex]_{0}[/tex]Cos[tex]\theta[/tex]

    a[tex]_{x}[/tex]dv[tex]_{}x[/tex]/dt = 0

    V[tex]_{x}[/tex]=Initial VCos[tex]\theta[/tex] = dx/dt

    Integrate and get
    x=Initial V(Cos[tex]\theta[/tex])(t)
    x=10(Cos80)(t)


    Y-direction

    a[tex]_{}y[/tex]=-9.81 m/ss

    V[tex]_{}y[/tex]=-10Sin80



    Im not sure if Im using the correct angle for theta (80 or 50) and Im stuck on the y-direction.
    Can you help?
     

    Attached Files:

  2. jcsd
  3. Jan 23, 2008 #2
    never integrate projectile equations is all that what i will tell ya...

    think differently....
     
  4. Jan 23, 2008 #3

    andrevdh

    User Avatar
    Homework Helper

    What you can try is develop the kinematic equations normal to and along the slope. The accelerations are the components of g in the respective directions. You then set the normal position coordinate to zero as a condition to find the range .
     
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