Projectile Problem: Find "d" on 10° Incline

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To find the distance "d" on a 10° incline, the key is to break down the projectile motion into horizontal and vertical components. The horizontal speed is calculated as 80cos55, resulting in approximately 45.89 ft/s. To determine the height at which the ball impacts the ground, use the relationship between height and horizontal distance, applying the tangent of the incline angle. This leads to two equations involving time and height, allowing for the calculation of time of flight. Solving these equations will yield the desired distance "d."
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Homework Statement


if20rc.jpg


There is the question I am having trouble with. All the data is given in the image. I am to find "d". The slope being on an angle is what is throwing me off. It would be simple enough if the ground was perfectly horizontal, but I am not sure how to handle the 10 degree incline.
My first thought was to make it as the golf ball was hit horizontally and at an angle of 55 degrees. I am not sure how to figure out the distance "d" though.

Any help would be greatly appriciated

Homework Equations



s=vot + 1/2 at^2

v=vo + at

V^2=vo^2 + 2as

The Attempt at a Solution


I am not sure where to start.
 
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Find the horizontal speed. Determine the height at B. Plug that time into your equation for height: h = v_yt - .5gt^2 to find the time of flight. Put that value of t into your equation for horizontal speed.

AM
 
Thanks for the reply.

I have the horizontal speed as 80cos55 = 45.89ft/s

I am unsure of how to calculate the height at which the ball hits the ground. Could someone shed some light as to how I would go about this.

Thanks in advance.
 
The height divided by the horizontal distance traveled (vxt) is tan(10).

This equation for h, combined with h = v_{0y}t -\frac{1}{2}gt^2 gives you two equations and two unknowns. So you can solve for t.

AM
 
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