Proof involving the sum of squared integers

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Homework Help Overview

The discussion revolves around a theorem concerning the representation of numbers in the set {99, 999, 9999, ...} as sums of squared integers. The original poster asserts that these numbers cannot be expressed as the sum of two squared integers, while at least one can be represented as the sum of three squared integers. The conversation explores logical frameworks and mathematical reasoning related to this theorem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of logical statements to represent the theorem, with some questioning the definitions of the components involved. There is also mention of using remainders to analyze the properties of these sums.

Discussion Status

The discussion is active, with participants providing insights into how to approach the proof. Some have offered examples and suggested methods for testing the conditions of the theorem, while others seek clarification on the logical structure and the role of remainders in the analysis.

Contextual Notes

Participants note the need to demonstrate both parts of the theorem separately and discuss the implications of modular arithmetic in proving the claims. There is an acknowledgment of the constraints of the problem as it relates to homework rules and the exploration of mathematical properties.

Entropee
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Homework Statement



Theorem: the numbers in the set {99, 999, 9999, ... } cannot be written as two squared integers, but at least one can be expressed as the sum of 3 squared integers.


Homework Equations



Well there are a lot of examples but let's go with 32 + 32 + 92 = 99

We may have to use Euclid's division algorithm as well.


The Attempt at a Solution



If we call the first part P and the second part Q then we can assume \negP \vee \negQ, and try to show a contradiction here.
 
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Entropee said:
If we call the first part P and the second part Q then we can assume \negP \vee \negQ, and try to show a contradiction here.
What is P, what is Q?

I would consider remainders here.
 
Sorry I'm on an ipad and was being lazy haha. Let p stand for "the numbers in that set cannot be written as two squared integers" and Q stand for "at least one number in the set can be represented as three integers squared." How should remainders be used here?
 
Just show both of them separately, there is no need to start with logical statements. You found an example how at least one of those numbers can be written as sum of three squares. Fine, this part is done. Now you have to show that none of those numbers is the sum of two squares.

How should remainders be used here?
As always. Test if an equality can hold mod some number - if not, it cannot be true at all.
 

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