Proof of Cauchy Schwarz for complex numbers

AI Thread Summary
The discussion revolves around proving the Cauchy-Schwarz inequality for complex numbers by manipulating the expression <x - ty, x - ty>, where t is defined as <x,y>/<y,y>. Participants are attempting to simplify the equation but face challenges in eliminating the conjugate notation represented by "*". Suggestions include further simplification of the inner product <x,ty> and making the substitution for t to facilitate the proof. Clarifications are made regarding the notation, specifically that "*" denotes the complex conjugate. The conversation highlights the complexities involved in handling inner products in the context of complex vector spaces.
dispiriton
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Homework Statement


I am told to try and solve <x - ty, x - ty> where t = <x,y>/<y,y>
However, I am stuck at that equation and unable to manipulate it to get rid of the *

Homework Equations





The Attempt at a Solution


<x - ty, x - ty> = <x,x> - <x,ty> - <ty,x> + <ty,ty>
= mod(x)^2 + mod(y)^2 (t^2) - t*<x,y> - (<x,ty>)*
 
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dispiriton said:

Homework Statement


I am told to try and solve <x - ty, x - ty> where t = <x,y>/<y,y>
However, I am stuck at that equation and unable to manipulate it to get rid of the *

Greetings dispiriton! What do you mean by "the *"?
 
dispiriton said:
<x - ty, x - ty> = <x,x> - <x,ty> - <ty,x> + <ty,ty>
= mod(x)^2 + mod(y)^2 (t^2) - t*<x,y> - (<x,ty>)*

You could simmplify this further by working out <x,ty>*. Try to get thet out of the inproduct.

Then, make the substitution t=<x,y>/<y,y>...
 
Undoubtedly0 said:
Greetings dispiriton! What do you mean by "the *"?

Its sort of like the "bar" where it is the conjugate.
 
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