Proof of Complex Conjugates and Real Coefficients | Complex Numbers Homework

AI Thread Summary
Two complex numbers, k and z, are complex conjugates if and only if the polynomial (x-k)(x-z) has real coefficients. The user has established that if k = a + bi and z = a - bi, then the sum of k and z is real, and the product is also real. To prove that the polynomial has real coefficients, the user is encouraged to expand (x-k)(x-z) and check for any remaining complex components. The discussion highlights the importance of thorough verification in mathematical proofs. Engaging with the problem directly is suggested as a more effective approach than seeking shortcuts.
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Homework Statement



I have two complex numbers that are non real, k and z. K and z are going to be complex conjugates if and only if the product (x-k)(x-z) is a polynomial with real coefficients.

Here is my answer :

k=a+bi

z=c+di

(x-k)(x-z) = x^2 -(k+z)x+kz

Homework Equations

The Attempt at a Solution


I was able to prove that a=c and d=-b (I have proven they're conjugatCes)

But because this is a if and only if, I must prove that if they're conjugates, then the coefficients are real. How do I do that ?
 
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So k = a + bi and z = a - bi. Now write out (x-k)(x-z) and see if there's anything complex left over or not !
 
BvU said:
So k = a + bi and z = a - bi. Now write out (x-k)(x-z) and see if there's anything complex left over or not !
To be honest, I did think about doing that but I was lazy and didn't try it and went just to ask this question... Thank you !
 
Being lazy is often a good quality for finding an economic way out of a problem :smile:
 
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