Proof of Formula for Advanced Calculus: Int. from a(t) to b(t)

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Homework Help Overview

The discussion revolves around the proof of a formula related to the differentiation of an integral with variable limits, specifically focusing on the expression involving the function \( f(t, \tau) \) and its partial derivative with respect to \( t \). The subject area is advanced calculus, particularly the application of the Fundamental Theorem of Calculus in a multivariable context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need for references that elucidate the proof of the formula rather than providing a direct solution. Some explore the implications of the Fundamental Theorem of Calculus and the conditions under which limits and integrals can be exchanged. Others question the correctness of the formula itself and suggest visualizing the terms in relation to the area under the curve.

Discussion Status

The conversation is ongoing, with participants offering insights into the conceptual understanding of the problem. There is a mix of attempts to clarify the formula and suggestions for visual learning approaches. No explicit consensus has been reached regarding the correctness of the formula, but there is a productive exchange of ideas and perspectives.

Contextual Notes

Some participants express uncertainty about the starting point for proving the formula and emphasize the importance of understanding the underlying principles rather than memorizing the formula itself. There are also indications of differing interpretations regarding the signs of the terms in the formula.

alfredblase
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I'm looking for a book/paper/online source where the following formula is shown to be true:

[tex]\frac d{dt} \int_{a(t)}^{b(t)} f(t,\tau)d\tau =\int_{a(t)}^{b(t)} \frac {\partial f(t,\tau)}{\partial t} d\tau\,+\, \frac {da(t)}{dt}f(t,a(t))\,-\, \frac {db(t)}{dt}f(t,b(t))[/tex]

I know one should post attempts at solving the problem but to be honest I wouldn't know where to start. That's one of the reasons why I asked for a reference that would explain/elucidate the proof rather than the proof itself (as well as such a source probably being very useful to me in general). I will say that I can show the Fundamental Theorem of Calculus to be true where the integrand is a function of only one variable if that helps..

Thanks for taking the time to read. Any help you offer will be very much appreciated.
 
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When the bounds are independent of t, you have:

[tex]\frac{d}{dt} \int_a^b f(t,\tau)dt = \lim_{h \rightarrow 0} \frac{1}{h} \left( \int_a^b f(t+h,\tau)d\tau-\int_a^b f(t,\tau)d\tau \right)[/tex]

[tex]=\lim_{h \rightarrow 0} \int_a^b \frac{f(t+h,\tau)-f(t,\tau)}{h} d\tau[/tex]

If you could justify exchanging the limit and integral, you'd get that this is equal to:

[tex]=\int_a^b \lim_{h \rightarrow 0} \frac{f(t+h,\tau)-f(t,\tau)}{h} d\tau = \int_a^b \frac{\partial f(t,\tau)}{\partial t}d \tau[/tex]

Then you can get the formula you mentioned by treating the integral as a function F(a,b,t) and using the chain rule and the fundamental theorem of calculus.

One time you can justify switching the limit and the integral is when the derivative is bounded on the integration range, which would be true, eg, if the function was continuously differentiable and the integral was finite.
 
Last edited:
alfredblase said:
I'm looking for a book/paper/online source where the following formula is shown to be true:

[tex]\frac d{dt} \int_{a(t)}^{b(t)} f(t,\tau)d\tau =\int_{a(t)}^{b(t)} \frac {\partial f(t,\tau)}{\partial t} d\tau\,+\, \frac {da(t)}{dt}f(t,a(t))\,-\, \frac {db(t)}{dt}f(t,b(t))[/tex]

I know one should post attempts at solving the problem but to be honest I wouldn't know where to start. That's one of the reasons why I asked for a reference that would explain/elucidate the proof rather than the proof itself (as well as such a source probably being very useful to me in general). I will say that I can show the Fundamental Theorem of Calculus to be true where the integrand is a function of only one variable if that helps..

Thanks for taking the time to read. Any help you offer will be very much appreciated.

Perhaps it will help if you can visualize where the terms in the derivative come from in terms of the area under the curve.
 

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"Perhaps it will help if you can visualize where the terms in the derivative come from in terms of the area under the curve."

Indeed it will. It's more useful to learn how to do that than try to remember "the formula". Learning that skill will also tell you that your equation is wrong, just by looking at it - the da/dt term should be minus and the db/dt term should be plus.

I don't have a book recommendation (I learned this stuff a very long time ago) but try and find a book that explains the principles with pictures, rather than just proving things formally.

Learning to think these things out for yourself is like learning to ride a bike, once you have "got it" you will never forget how to do it. You can then get by without remembering formulas, or having to look them up in books.
 
thankyou so much OlderDan for your awesome and pedagogical rendition of the problem and AlephZero for that inspirational and, in my humble opinion, profound message :smile:

I'll be sure to apply the methods you described in the future and hopefuly, as in this case, with much success.

:D
 

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