- #1
Tony11235
- 255
- 0
Prove that a stick of proper length L has a length L' in a frame in which it moves with speed v along a line that makes an angle theta with it's length is given by
[tex] L' = L \sqrt{\frac{1-v^2 / c^2}{1 - (v^2 / c^2)\sin^2{\theta}}}[/tex]
My problem here is the picture I think. So the stick overall is moving with speed v, but the stick is not necessarily parallel to v, but at an angle created by the direction of v and the stick?
[tex] L' = L \sqrt{\frac{1-v^2 / c^2}{1 - (v^2 / c^2)\sin^2{\theta}}}[/tex]
My problem here is the picture I think. So the stick overall is moving with speed v, but the stick is not necessarily parallel to v, but at an angle created by the direction of v and the stick?
Last edited: