Properties of Gases: Volume Change with Cooling & Pressure Increase

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The discussion revolves around calculating the volume of hydrogen gas when it is cooled from 300 K to 150 K and the pressure is increased from 203 kPa to 600 kPa. The ideal gas law is suggested as the method for solving the problem, using the formula P1V1/T1 = P2V2/T2. The user expresses confusion due to missing a lesson on this topic and seeks clarification on how cooling and pressure changes impact gas volume. The solution involves substituting the known values into the ideal gas equation to find the new volume. Understanding these principles is crucial for accurately determining gas behavior under varying conditions.
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Homework Statement


A volume of 2.40x10^-3 m^3 of hydrogen gas is enclosed in a cylinder with a movable piston at 300 K under a pressure of 203 kPa (2.00 atm). The density of hydrogen under these conditions is 0.180 kg m^3.

1. The gas is cooled down to 150 K, and the pressure is increased to 600 kPa. Calculate the volume in the gas.

2. The attempt at a solution
1.) How does gas cooling down and pressure increasing affect the volume?

I was not here for this lesson, hence I have no idea what I'm doing. Thanks for the help.
 
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Ohm. said:

Homework Statement


A volume of 2.40x10^-3 m^3 of hydrogen gas is enclosed in a cylinder with a movable piston at 300 K under a pressure of 203 kPa (2.00 atm). The density of hydrogen under these conditions is 0.180 kg m^3.

1. The gas is cooled down to 150 K, and the pressure is increased to 600 kPa. Calculate the volume in the gas.

2. The attempt at a solution
1.) How does gas cooling down and pressure increasing affect the volume?

I was not here for this lesson, hence I have no idea what I'm doing. Thanks for the help.
Simply approach is to use ideal gas law: PV = mRT. There should be no mass entering or leaving the cylinder so: P1 V1 / T1 = P2 V2 / T2. Solve for V2 and substitute numerical values.
 
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