Prove a + ar + ar^2 + + ar^n < a/r - 1

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SUMMARY

The discussion focuses on proving the inequality \( a + ar + ar^2 + \ldots + ar^n < \frac{a}{r} - 1 \) for \( a > 0 \) and \( 0 < r < 1 \). Participants emphasize that the series represents a geometric progression, and the sum can be derived using the formula \( \frac{a}{1 - r} \). It is established that as \( n \) approaches infinity, the sum converges, confirming that it remains less than \( \frac{a}{r} - 1 \) under the specified conditions.

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Homework Statement



Show that, if a>0 and 0<r<1, then for all n>=1 , a+ar+ar^2+...+ar^n < a/r -1



Homework Equations





The Attempt at a Solution



could someone please give me some hints as to how to start this questions. thanks
 
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Hello,

http://en.wikipedia.org/wiki/Geometric_progression

The series you have is a geometric progression, follow the derivation for the sum of a geometric progression on the wikipedia page. Once you have derived the sum take the limit as n goes to infinity.

If this is a/(1 - r), or less, you have shown that the sum can never be greater than a/(1-r).

To take the limit you will also need to explicitly show that the series converges for some range of r.
 

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