Prove cauchy sequence and thus convergence

manooba
Messages
8
Reaction score
0
Let (Xn) be a sequence satisfying

|Xn+1-Xn| ≤ λ^n r

Where r>0 and λ lies between (0,1). Prove that (Xn) is a Cauchy sequence and so is convergent.
 
Physics news on Phys.org
I have a hunch that you could use two facts:

1) for every ε > 0 there exists some natural number N such that λ^N r < ε
2) the triangle inequality
 
manooba said:
Let (Xn) be a sequence satisfying

|Xn+1-Xn| ≤ λ^n r

Where r>0 and λ lies between (0,1). Prove that (Xn) is a Cauchy sequence and so is convergent.

I posted the solution of that with r=1 in a similar thread called cauchy sequence problem
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top