Prove Invertibility of nxn Matrix AB=I

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SUMMARY

Every n x n matrix A that has a corresponding n x n matrix B such that AB = I is guaranteed to be invertible. This conclusion is derived from the properties of determinants, specifically the equation \det(AB) = \det(A) * \det(B). If AB equals the identity matrix I, then \det(AB) equals 1, which implies that both \det(A) and \det(B) must be non-zero, confirming the invertibility of matrix A.

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Homework Statement



Prove that every n x n matrix A for which there exists an n x n matrix B such that AB = I must be invertible. Hint: Use properties of determinants.

Homework Equations



None that I am aware of.

The Attempt at a Solution



I tried finding the inverse of the matrix and multiplying by an elementary matrix. I also tried finding the determinants of a simple matrix and using it's properties but nothing is working :(
 
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sheldonrocks97 said:

Homework Statement



Prove that every n x n matrix A for which there exists an n x n matrix B such that AB = I must be invertible. Hint: Use properties of determinants.

Homework Equations



None that I am aware of.

The Attempt at a Solution



I tried finding the inverse of the matrix and multiplying by an elementary matrix. I also tried finding the determinants of a simple matrix and using it's properties but nothing is working :(

You are supposed to use the fact that \det (AB) = (\det A) (\det B).
 

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