Prove: Mean Value Theorem & Rolle's Theorem | At Most 1 Fixed Point

DeltaIceman
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Homework Statement


A number a is called a fixed point if f(a)=a. Prove that if f is a differentiable function with f'(x)=1 for all x then f has at most one fixed point.


Homework Equations


In class we have been using Rolle's Theorem and the Mean Value Theorem.


The Attempt at a Solution


In all honest I wasn't sure where to start but this is what I've come up with so far. Knowing that the slope or f'(x)=1 then the original function must have been something like f(x)= x + k. Considering k as a constant that could exist or could not. Then the function either has no fixed point. Or every point of the function is fixed. Therefore giving us a contradiction in the statement. Meaning that this statement cannot be possible. We worked a couple of these in class and I didn't really know how to approach this problem. What I did kinda makes sense to me although it doesn't seem like this should be the answer. Any help would be appreciated thanks!
 
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Let x=a be a fixed point of f. Then by the definition of "fixed point", f(a)=a+k=a. Consider 2 cases: k=0 and k\neq 0.
 
Hold on a second...The proposition in the problem statement is false. Let f(x)=x. Then f'(x)=1 for all x, and every point is a fixed point!
 
Agreed.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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